Question

A light bulb has a resistance of 5 ohms and a maximum current of 10 A. How much voltage can be applied before the bulb will break?

Answer 1

Resistance of bulb = 5 ohms

Maximum current = 10 A

=> Voltage = Current × Resistance

= (10×5)V = 50 V

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Answer 2

Answer: according to ohms law voltage is directly proportional to current

voltage is also proportional to resistance  so the formula becomes V=IR

Explanation:

V=?

R=5 ohms

I=10A

if V=IR

then V =10X5

V=50 Answer