Question

a light bulb has rating 200 watt 220 volt. find the peak value of the current

Answer 1

Power = 200 W.

Potential = 220 V.

We know that,

Power = Potential × Current.

∴ Current = Power/Potential

⇒ I = P/V

∴ I = 200/220

⇒ I = 0.91 A.

Therefore, Peak Value of Current or the Current rating of the Bulb is 0.91 A.

Hope it helps.