A light ray falls on one of the faces of a prism at an angle of 40°,so that it suffers angle of minimum deviation of 30°.find the angle of prism and angle of refraction at the given surface
Answers
Answered by
48
minimum deviation= 2i-A
30=2*40-A
A=50
refractive index=sin i / sin r
sin r =sin40/1.5
r=25°
30=2*40-A
A=50
refractive index=sin i / sin r
sin r =sin40/1.5
r=25°
Answered by
10
Answer: Angle of refraction is 25 degrees and angle of prism is 50 degrees
Explanation:
WKT, IN ANGLE OF MINIMUM DEVIATION CONDITION ,
i1 is i2
so wkt,
A+D= i1+i2
A+30=2i
A+30=2(40)
A=80-30=50 DEGREES
WKT,
A = R1+R2
HERE ,R1=R2
50/2= R
R=25
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