A light ray passes from liquid to air. find the value of critical angleif velocity in air and liquid are 3*10^8m/s and 1.5*10^8m/s respectively
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Refractive index of air = 1 = μ2
Refractive index of the liquid
= speed of light in air/speed of light in medium
= 3x10⁸/1.5x10⁸
= 2 = μ1
Critical angle
= sin⁻¹(μ2/μ1)
= sin⁻¹(1/2)
= sin⁻¹0.5
= 30°
Hence, the critical angle is 30°.
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