Question

A lighthouse is 25 m high. From the top of the lighthouse, the angles of depression of two buoys due north of it are 45° and 30°. Given that:
$\tan(30) = \frac{1}{ \sqrt{3} }$
show that the distance x, in metres, between the buoys is:
$25( \sqrt{3} - 1)$
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Answer 1

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Answer 2

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