Question

A line goes through points ( − 3 , 1 ) and ( 7 , 6 ) .

Answer 1

Step-by-step explanation:

Solution of your question.

Answer 2

Answer:

The equation of the line that passes through points (-3, 1) and (7,6) is 2y -x = 5

Explanation:

Given Points : (-3, 1) and (7,6)

To Calculate: The equation of the line passing through the given lines

Solution :

At first, we will calculate the value of the slope (m)

The formula for evaluating the slope is

$m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

So, Putting the values in the given equation, we have :

$m = \frac{6 -1 }{7-(-3)} =\frac{5}{10} =\frac{1}{2}$

Thus, m = 1/2

Now, the general equation of the line whose slope is 1/2 and the

the line passes through the point (-3, 1) given by

$y -y_{1} =m(x-x_{1} )$

Now, putting the values, in the equation, we get,

$y - 1 = \frac{1}{2} (x - (-3))\\\\2(y - 1) = x + 3\\\\2y - 2 = x + 3\\\\2y - x = 3 +2 \\\\2y - x = 5$

Thus, The equation of the line that passes through points (-3, 1) and (7,6) is 2y -x = 5

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