A line has a slope of 4 and lies on the point (2, 4). What is the equation of that line in slope-intercept form?
Answers
Solution:
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Slope-intercept form of a line:
y = mx+c
Where,
slope = m
y-intercept = c
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Here,
slope (m) = 4
and This line passing through the point (2,4).
y = mx+c
=> y = 4x+c
substitute (2,4) in the equation,
to get c value,
=> 4 = 4×2 + c
=> 4 = 8 + c
=> 4-8=c
=> -4=c
Therefore,
Required equation:
y=4x+(-4)
Or
y=4x-4
••••
Answer:
y = 4x - 4
Step-by-step explanation:
Steps as follow:
1. Define the general format of a linear equation
2. Solve gradient, m
3. Solve y - intercept, c
4. Define equation
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STEP 1: Define general equation:
General equation of a line has the format y = mx + c
where m is the gradient and c, the y-intercept
STEP 2: Solve Gradient
Given that the slope is 4
y = mx + c
/* substitute m = 4 into the equation */
y = 4x + c
STEP 3: Solve y-intercept:
Given that the the equation passed through (2, 4)
y = 4x + c
/* sub x = 2, y = 4 into the equation and solve for c */
4 = 4(2) + c
/* remove the bracket */
4 = 8 + c
/* subtract 8 from both sides */
-4 = c
/* make c the subject */
c = -4
STEP 4: Form the equation:
y = mx + c
/* sub m = 4 and c = -4 */
y = 4x - 4
Answer: y = 4x - 4