Math, asked by fifi4085, 11 months ago

A line has a slope of 4 and lies on the point (2, 4). What is the equation of that line in slope-intercept form?


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Answers

Answered by mysticd
2

Solution:

____________________

Slope-intercept form of a line:

y = mx+c

Where,

slope = m

y-intercept = c

_________________________

Here,

slope (m) = 4

and This line passing through the point (2,4).

y = mx+c

=> y = 4x+c

substitute (2,4) in the equation,

to get c value,

=> 4 = 4×2 + c

=> 4 = 8 + c

=> 4-8=c

=> -4=c

Therefore,

Required equation:

y=4x+(-4)

Or

y=4x-4

••••

Answered by TooFree
1

Answer:

y = 4x - 4

Step-by-step explanation:

Steps as follow:

1. Define the general format of a linear equation

2. Solve gradient, m

3. Solve y - intercept, c

4. Define equation

----------------

STEP 1: Define general equation:

General equation of a line has the format y = mx + c

where m is the gradient and c, the y-intercept

STEP 2: Solve Gradient

Given that the slope is 4

y = mx + c

/* substitute m = 4 into the equation */

y = 4x + c

STEP 3: Solve y-intercept:

Given that the the equation passed through (2, 4)

y = 4x + c

/* sub x = 2, y = 4 into the equation and solve for c */

4 = 4(2) + c

/* remove the bracket */

4 = 8 + c

/* subtract 8 from both sides */

-4 = c

/* make c the subject */

c = -4

STEP 4: Form the equation:

y = mx + c

/* sub m = 4 and c = -4 */

y = 4x - 4

Answer: y = 4x - 4

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