A line is drawn parallel to the side BC of triangle ABC which cuts side AB atP and side AC at Q. If AB=6cm, CA=6cm and AQ=4.2cm, find the length of AP
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Answer:
Step-by-step explanation: -
PQ|| BC (given)
Angle ABC = Angle APQ (alt. Angles)
Triangles APQ ~ ABC
AP/AB = AQ/AC
AP/6 = 4.2/6
AP = 4.2 cm
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