A line L is perpendicular to the line 5x-y=1
and the area of the triangle formed by the line L and coordinate axes is 5. The equation of the line L is [IIT 1980; RPET 1997]
A) x+5y=5 B) x+5y=\pm 5\sqrt{2} C) x-5y=5 D) x-5y=5\sqrt{2}
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Answered by
2
eq of L is x+5y=k
intersrcting axes at (k,0) & (0,k/5)
hence area is
k^2/2*5=5
k=,5β2
ans is B
intersrcting axes at (k,0) & (0,k/5)
hence area is
k^2/2*5=5
k=,5β2
ans is B
Answered by
1
Answer:
answer is c
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