A line makes positive intercepts on coordinate axes whose sum is 7 and it passes through (-3,7) find its equation.
Answers
Step-by-step explanation:
There could be multiple answers to this question.
x/a + y/b = 1
If we write the equation of a straight line in this form, then the x axis intercept is a and y axis intercept is b. Given a+b = 5
bx + a y = ab
(5 - a) x + a y = a (5 - a)
Point P (-3,4) lies on the straight line.
-3 (5-a) + 4 a = 5a - a²
-15 + 3a + 4a = 5a - a²
a² + 2a - 15 = 0
(a + 5)(a-3) = 0 a = -5 or 3
b = 10 or 2
So equations of the two straight lines are :
10 x - 5y = -50 or 2 x - y + 10 = 0 and 2 x + 3 y = 6
other
x/a + y/b = 1
If we write the equation of a straight line in this form, then the x axis intercept is a and y axis intercept is b.
Given a+b = 5
bx + a y = ab
(5 - a) x + a y = a (5 - a)
Point P (-3,4) lies on the straight line.
-3 (5-a) + 4 a = 5a - a²
-15 + 3a + 4a = 5a - a²
a² + 2a - 15 = 0
(a + 5)(a-3) = 0 a = -5 or 3
b = 10 or 2
So equations of the two straight lines are :
10 x - 5y = -50 or 2 x - y + 10 = 0 and 2 x + 3 y = 6
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