a line makes positive intercepts on coordinate axis whose sum is 7 and it passes through(-3,8) find the equation
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Step-by-step explanation :
Let us take the equation of a line in intercept form as follows,
x/a + y/b = 1 ..... (i)
By the given condition,
a + b = 7 ..... (ii)
Also given that, (i) no. line passes through the point (- 3, 8). Then from (i), we write
- 3/a + 8/b = 1
or, - 3b + 8a = ab
or, - 3 (7 - a) + 8a = a (7 - a), by (ii)
or, - 21 + 3a + 8a = 7a - a²
or, a² + 4a - 21 = 0
or, a² + 7a - 3a - 21 = 0
or, a (a + 7) - 3 (a + 7) = 0
or, (a + 7) (a - 3) = 0
Either a + 7 = 0 or, a - 3 = 0
i.e., a = - 7, 3
Given that a > 0; then a = 3 only.
Then b = 4.
From (i), we get the equation of the required line
x/3 + y/4 = 1
or, 4x + 3y = 12 .
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