A line makes zero intercepts on x axis and y axis and perpendicular to the line 3x+4y=-6then the equation is
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Given line 3x+4y=-6
Rearrange to get y= (-3/4)x + (-3/2)
Hence, slope of the line is -3/4
Since, the required line is perpendicular to the given line, then slope of given line is 4/3. Now, since, the required line make zero intercepts with X-axis and y-axis, the the line is passing through origin (0,0).
Therefore equation of the required line through (0,0) is y-0 = (4/3)(x-0) which gives 4x-3y=0.
I hope it's correct.
PrithwiCC:
plz correct that line, the slope of the required line is 4/3. By mistake I wrote "given line".
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