A line passes through the point P(3,2) and cuts off positive intercepts on x axis and y axis in the ratio 3:4.Find the equation of the line
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A/Q it cutoff intercept in ratio = 3 : 4
let x intercept be a then y intercept = 4a/3
now eq would be x/a + y / (4a/3) = 1 ⇒ x/a + 3y/4a = 1
(3,2) satisfies it
⇒3/ a + 3 (2)/4a = 1 ⇒ 12+6/4a = 1 ⇒ 18 = 4a ⇒ a = 9/2
so x intercept = 9/2 and y intercept = 6
so eqn gonna be x/(9/2) + y/6 = 1
⇒ 4x + 3y = 18
any doubts, ask.
let x intercept be a then y intercept = 4a/3
now eq would be x/a + y / (4a/3) = 1 ⇒ x/a + 3y/4a = 1
(3,2) satisfies it
⇒3/ a + 3 (2)/4a = 1 ⇒ 12+6/4a = 1 ⇒ 18 = 4a ⇒ a = 9/2
so x intercept = 9/2 and y intercept = 6
so eqn gonna be x/(9/2) + y/6 = 1
⇒ 4x + 3y = 18
any doubts, ask.
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