Question

A line passing through (3, 1) makes a triangle of area 8 units in the first quadrant with two axis. Find the

equation of this line.​

Answer 1

Answer:

4b+a=16, that is, a=16–4b. Again, put this value of a in equation 2 and solve quadratic in variable b.

So, from equation 2, a=16/2=8. Hence, the equation of the line is (x/8)+(y/2)=1, which on simplification gives x+4y=8.