A line passing through (a,2a) and (-2,3) is perpendicular to the line 4x+3y+5=0. find the value of a
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4x+3y=-5
(1,-3),(-2,1) will satisfy the equation
if line passes perpendicularly then,
draw a line perpendicular to the equation passing through (-2,3)
extend the line
it meets the point (3,6)
which is in the form of (a,2a)
so a=2
(1,-3),(-2,1) will satisfy the equation
if line passes perpendicularly then,
draw a line perpendicular to the equation passing through (-2,3)
extend the line
it meets the point (3,6)
which is in the form of (a,2a)
so a=2
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