Question

A line Segment 560 CM long is to be divided into two parts in the ratio of 2:5. Find the length of each part.

Answer 1

Let the each divided parts be 2x & 5x.

Now,

$\bf \: Length \: \: of \: \: {1}^{st} \: \: part = 560 \times \frac{2}{7} \\ \\ \bf\: \: \: \: \: \: \: \: \: \: \: \: = > 80 \times 2 = { \red{160 \: cm}}$

$\bf \: Length \: \: of \: \: {2}^{nd} \: \: part = 560 \times \frac{5}{7} \\ \\ \bf\: \: \: \: \: \: \: \: \: \: \: \: = > 80 \times 5 = { \red{400 \: cm}}$

Hence, The line segment 560 cm long when divided into two parts in the ratio of 2:5 will measure 160 cm & 400 cm.

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Answer 2

Step-by-step explanation:

Let the each divided parts be 2x & 5x.

Now,

\begin{gathered}\bf \: Length \: \: of \: \: {1}^{st} \: \: part = 560 \times \frac{2}{7} \\ \\ \bf\: \: \: \: \: \: \: \: \: \: \: \: = > 80 \times 2 = { \red{160 \: cm}}\end{gathered}

Lengthof1

st

part=560×

7

2

=>80×2=160cm

\begin{gathered}\bf \: Length \: \: of \: \: {2}^{nd} \: \: part = 560 \times \frac{5}{7} \\ \\ \bf\: \: \: \: \: \: \: \: \: \: \: \: = > 80 \times 5 = { \red{400 \: cm}}\end{gathered}

Lengthof2

nd

part=560×

7

5

=>80×5=400cm

Hence, The line segment 560 cm long when divided into two parts in the ratio of 2:5 will measure 160 cm & 400 cm.