A line segment AB
is bisected at point P and through point P another line segment
PQ, which is perpendicular to AB, is drawn. Show that: QA = QB.
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Answer:
Given:A line segment AB is bisected at point P
=> AP=PB
Also, QP is perpendicular to AB
To Prove: QA =QB
Proof: In triangles APQ & BPQ
AP=PB( given)
<APQ=<BPQ (each 90)
QP=QP (common)
Therefore, triangles APQ =~ BPQ (by SAS congruence rule)
=> QA = QB(by C. P. C. T)
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