Math, asked by arbazalam12, 1 year ago

A line segment AB is divided internally at point C in the ratio 3:5, then ​

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Answers

Answered by snehaa2830
4

given that the ratio is 3:5 so let AC be 3x and BC be 5x.

for more detail do comment.

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arbazalam12: but that's not in the option
snehaa2830: accha suno fir
snehaa2830: 5AC = 3 BC aaya
snehaa2830: we know that AB = AC + CB
snehaa2830: now you'll get the answer
shubhu4444: hi
shubhu4444: sn
shubhu4444: eh
shubhu4444: a.
shubhu4444: nice dp
Answered by santy2
11

Answer:

Choice 4

Step-by-step explanation:

Since the point C divided the line AB internally then point C is between A and B.

This means that we have lengths :

AC and BC

The ratio of the division is given by :

AC : BC = 3:5

We can rewrite this as follows:

AC/BC = 3/5

Eliminating the denominators we have.;

Hence we have that :

5AC = 3BC

Now AB = sum of the ratios (5 + 3) = 8

AC : AB = 3 : 8

AC/AB = 3/8

8AC = 3AB

The correct answer is thus choice 4.

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