Question

a line segment ab is equal to 8 cm is divided in the ratio 3 is to 2 by a Ray at point P lies on AB the distance of point P from a is

Answer 1

The distance of point P from A =4.8 cm

Step-by-step explanation:

Length of line segment AB=8 cm

Ratio=3:2

Let PQ is a ray which intersect the segment AB at point P

According to question

$\frac{AP}{PB}=\frac{3}{2}$

$3AP=2PB$

$PB=\frac{2}{3}AP$

AB=AP+PB

By using segment addition property

Substitute the values then we get

$8=AP+\frac{2}{3}AP$

$8=\frac{3AP+2AP}{3}$

$8=\frac{5}{3}AP$

$AP=\frac{3}{5}\times 8$

$AP=\frac{24}{5}$

AP=4.8 cm

Hence, the distance of point P from A =4.8 cm

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