A line segment AB of length 7.8 cm is divided internally at P in the ratio 6 : 7. Then measure of AP is
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Step-by-step explanation:
DRAW A LINE SEGMENT AB = 7.8 CM
*DRAW AN ACUTE ANGLE FROM 'A' TO 'X'.
*DIVIDE 'AX' INTO 13 EQUAL PARTS ( 6+7=13)
*NAME THEM AS A1,A2,A3 ......….. A13.
*JOIN 'A13' AND 'B'
*DRAW A LINE PARALLEL TO 'A13B' WHICH INTERSECTS 'AB' AT 'C' AND THE POINT 'C' DIVIDES 7.8 CM IS LINE SEGMENT INTO THE RATIO OF 6:7.
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