A line segment is of length 5 units and one end is at the point (1,-2). If the abscissa of the other end is 4, then find its ordinate.
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Answer:
simple h
Step-by-step explanation:
Distance between two points =(x2−x1)2+(y2−y1)2
Given, one point =(2,−3)
Let, other point =(10,b)
absicca is x cordinate
∴ (10−2)2+(b+3)2=10
82+(b2+9+6b)=10
Squaring both the sides, we get
64+b2+9+6b=100
(b+3)2=36
∴ b+3=6 and b+3=−6
∴ b=3 and b=−9
values alag h dekh lena
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