A line through the point P(2, -3) meets the lines x -2y+7= 0 and x+3y-3=0 at the points A and B respectively. If P divides AB externally in the ratio 3:2 then find the equation of the line AB
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Answered by
5
we can find equation by hit and trial method
x=7-2y
3=7-2(2)
3=3
so this is equation is of line AB
x=7-2y
3=7-2(2)
3=3
so this is equation is of line AB
Answered by
2
we can find equation by hit and trial method
x=7-2y
3=7-2(2)
3=3
so this is equation is of line AB
Hope it was helpful for u
x=7-2y
3=7-2(2)
3=3
so this is equation is of line AB
Hope it was helpful for u
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