Question

A linear equation has solutions (-5,5) (0,0) and (5,-5) . Write the linear equation. Pls answer this question i will mark u as brainliest ....☺️☺️

Answer 1

Let us consider a linear equation ax + by + c = 0 … (i)

Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation

therefore it satisfies the Eq. (i), we get

At point(-2,2), -2a + 2b + c = 0 …(ii)

At point (0, 0), 0+0 + c = 0 ⇒ c = 0 …(iii)

and at point (2, – 2), 2a-2b + c = 0 …(iv)

From Eqs. (ii) and (iii),

c = 0 and – 2a + 2b + 0 = 0, – 2a = -2b,a = 2b/2 ⇒a = b

On putting a = b and c = 0 in Eq. (i),

bx + by + 0= 0 ⇒ bx + by = 0 ⇒ – b(x + y)= 0 ⇒ x + y = 0, b ≠ 0

Hence, x + y= 0 is the required form of the linear equation.

Hope it helps!!

Thank you ✌️

Answer 2

Answer:

The required linear equation is

x + y = 0

Step-by-step explanation:

Any linear equation is of the form

ax + by + c = 0 - - - - - - - - (1)

Since Equation (1) passes through (-5,5)

-5a + 5b + c = 0 - - - - - - - (2)

Equation (1) passes through (0,0)

c = 0 - - - - - - - (3)

Equation (1) passes through (5,-5)

5) 5a - 5b + c = 0 - - - - - - - (4)

From Equation (2) & Equation (4) using Equation (3)

5a- 5b = 0

So

a = b

From Equation (1) we get

ax + ay = 0

x + y = 0 ( Since a#0)

--------- which is the required linear equation