Question

a linear resistance potentiometer is 50 mm long and is uniformly wound with a wire having a resistance 10000 . under normal conditions, the slider is at the centre of the potentiometer. find the linear displacement when the resistance of the potentiometer is (i) 3850

Answer 1

ANSWER

a linear resistance potentiometer is 50 mm long and is uniformly wound with a wire having a resistance 10000 . under normal conditions, the slider is at the centre of the potentiometer. find the linear displacement when the resistance of the potentiometer is (i) 3850

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Answer 2

Answer:

The linear displacement when the resistance of the potentiometer is  5.75 mm

Explanation:

Given: Linear resistance potentiometer is 50 mm long and is uniformly wound with a wire having a resistance 10000 .

Find: linear displacement when the resistance of the potentiometer

Solution:

The resistance of potentiometer at the normal position= l0,000/2= 5000 Ω.

(i) Resistance of potentiometer wire per unit length= 10,000/50=200 Ω /mm.

(ii) Change in resistance of potentiometer from its normal position =5000-3850= 1150 Ω.

So, Displacement=("Change in resistance"   "Ω" )/"Resistance of potentiometer wire per unit length" =1150/200=5.75

(iii) Change in resistance of potentiometer from its normal position=7560-5,000 =2,560 Ω

So, Displacement =2560/200=12.55

Since one of the displacements represents a decrease and the other represents an increase in resistance of the potentiometer as compared with the resistance of the potentiometer at its normal position, the two displacements are in the opposite direction.

Resolution=minimum  measurable value of resistance *(/"Ω" )=0.05mm

=0.05mm.