Question

A liquid drop has 20 excess electrons.calculate charge on drop?

Answer 1

q=ne
=
$20 \times 1.6 \times {10 - 19}^{?}$

Answer 2

Given that,

Number of electron n= 20

We need to calculate the charge on drop

Using formula of charge

$Q= ne$

Where, Q = charge

n = number of electron

e = charge of electron

Put the value into the formula

$Q=20\times1.6\times10^{-19}$

$Q=3.2\times10^{-18}\ C$

Hence, The charge on drop is $3.2\times10^{-18}\ C$