A liquid drop of diameter d breaks into 27 tiny drops. The resultant change in energy is?
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radius of larger drop =R
radius of each small drop=r
vol. oh 27 small drops = vol. of the large drop
27*4/3*πr^3=4'3πR^3
r=R/3
surface area of large drop=24πR^2
surface area of 27 small drop=27*4πr^2
4*4π(R^3/3)=12πR^2
increase in surface area =12πR^2-4πR^2
=8πR^2
increase in energy =increase in surface area *surface tension =8πR^2*S
radius of each small drop=r
vol. oh 27 small drops = vol. of the large drop
27*4/3*πr^3=4'3πR^3
r=R/3
surface area of large drop=24πR^2
surface area of 27 small drop=27*4πr^2
4*4π(R^3/3)=12πR^2
increase in surface area =12πR^2-4πR^2
=8πR^2
increase in energy =increase in surface area *surface tension =8πR^2*S
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