Question

A liquid drop of radius R breaks into 64 tiny droplets each of radius r if the surface tension of liquid is T then gain in energy is

Answer 1

the density of the liquid be ρ.

Mass of the liquid drops must be equal to the total mass of the droplet

⟹R=4r

Change in surface area ΔA=64×4πr  

2

−4πR  

∴ ΔA=64×4π×r  

∴ Gain in energy E=TΔA=192πr  

Answer 2

Answer:

Explanation:

Let the density of the liquid be ρ.

Mass of the liquid drops must be equal to the total mass of the droplets.

∴ ρ×

3

4π

​

R

3

=64×ρ×

3

4π

​

r

3

⟹R=4r

Change in surface area ΔA=64×4πr

2

−4πR

2

∴ ΔA=64×4π×r

2

−4π(4r)

2

=192πr

2

∴ Gain in energy E=TΔA=192πr

2

T

Hope This helps you...