A liquid of density p and surface tension S rises to a height h in a capillary tube of diameter D. What is the weight of the liquid in the capillary tube? Take angle of contact to be 0º.
Answers
Answered by
18
Ф = Angle of contact = 0 deg.
S = surface tension
D/2 = radius of the tube
ρ = density of liquid
h = height of the column inside tube
The force of surface tension pulling the liquid upwards in the tube
= S * π D cosФ = π D S
The force pulling the liquid downwards = weight = W = πD²/4 * h * ρ * g
So: π D S = W = π/4 * D² h ρ g
height of liquid = h = 4 S/ [D h ρ g]
Weight = π D S or πD²/4 * h g ρ
S = surface tension
D/2 = radius of the tube
ρ = density of liquid
h = height of the column inside tube
The force of surface tension pulling the liquid upwards in the tube
= S * π D cosФ = π D S
The force pulling the liquid downwards = weight = W = πD²/4 * h * ρ * g
So: π D S = W = π/4 * D² h ρ g
height of liquid = h = 4 S/ [D h ρ g]
Weight = π D S or πD²/4 * h g ρ
Attachments:
kvnmurty:
click on red heart thanks above
Answered by
0
The liquid rises due to the forces of adhesion, cohesion, and surface tension. ... The formula for capillary rise can be derived by balancing forces on the liquid column. The weight of the liquid (πr2hρg π r 2 h ρ g ) is balanced by the upward force due to surface tension (2πrσcosθ 2 π r σ cos ).
refer to the attachment......
Attachments:
Similar questions