Physics, asked by Maruf14431, 9 months ago

A liquid of mass 100 g loses heat at a rate of 200 Js-l for 1 minute. If the temperature of the liquid drops by 100 0C, calculate the specific heat capacity of the liquid.

Answers

Answered by ridam1181

5

Answer:

Q=mc∆T

PT= mc ∆ T

Specific heat:

c= pt/mc∆T

=200×60/0.1×100

1200 J/kg/°c

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