Question

If 17 cos A=8,find 15 cosec A -8 sec A

Answer 1

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Question :-

If 17 cos A=8

Find 15 cosec A - 8 sec A

solution :-

17 cos A = 8

$Cos A = \frac{8}{17}$

• $Cos A = \frac{b}{h}$

$\frac{b}{h}=\frac{8}{17}$

b = 8

h=17

• applying Pythagoras theorem

$p^2 + b^2 = h^2$

$p^2 + 8^2 = 17^2$

$p^2 + 64 = 289$

$p^2 = 289 - 64$

$p^2 = 225$

$p = \sqrt 225$

$p = 15$

• finding value of cosec and sec

$cosec = \frac{h}{p}$

$cosec = \frac{17}{15}$

$sec = \frac{h}{b}$

$sec = \frac{17}{8}$

• putting value in equation

15 cosec A - 8 sec A

= $15 *\frac {17}{15} - 8* \frac {17}{8}$

= $17 - 17$

= $0$

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Answer 2

Answer:

o

Step-by-step explanation: