Question

A liquid rises through a height of 4 mm in tube of diameter 2 cm how much it will rise in tube of radius 3 mm.

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required height is 44.44 mm}}}$

Explanation:

radius of 2 cm tube=20/2 mm= 10mm

Volume of liquid displaced for 2 cm diameter= pi*(10)^2*4   (pi*r^2*h)

The volume displaced in the 2nd tube is equal

So, pi*(10)^2*4= pi*(3)^2*h  (h is the required height)

=>h=10^2*4/3^2

=>h=400/9 mm

=>h= 44.44 mm