Math, asked by rogith2519, 9 months ago

limit x tends to π/2 [sinx] where [] is greatest integer function is​

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Answered by Anonymous
0

 lim_{x -   > \pi/2}  \:  \: [sinx] \\  \\  =  [sin( \frac{ \pi}{2} )] \\  \\  = 1

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