a)List four characteristics of the image formed by a concave lens of
focal length 20 cm when the object is placed at a distance of 40 cm
from its optical centre.
b)The size of image of an object by a convex lens of focal length 20 cm
is observed to be reduced to rd of its size. Find the distance of the
object from the optical centre of the lens..
Answers
Answer:
A) The size of the image is two by third of the object and the image distance is 40/3. The image will be placed virtual and erect and diminished.
B)
object distance from the optical centre of the lens is 80cm.
explanation : focal length of convex lens , f = +20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = -1/3
we know, magnification of lens , m = v/u
so, v/u = -1/3
so, v = -u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(-u/3) - 1/u = 1/20
or, -3/u - 1/u = 1/20
or, u = -80 cm
hence, object is placed 80cm from the pole of convex lens.
a)hi mate,
Solution: object distance from the optical centre of the lens is 40cm.
explanation : focal length of concave lens , f = -20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = 1/3
we know, magnification of lens , m = v/u
so, v/u = 1/3
so, v = u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(u/3) - 1/u = 1/-20
or, 3/u - 1/u = 1/20
or, 2/u = 1/-20 cm
or, u = -40 cm
hence, object is placed 40cm from the pole of concave lens.
i hope it helps you.......
.
b)hi mate,
Solution: object distance from the optical centre of the lens is 80cm.
explanation : focal length of convex lens , f = +20cm
a/c to question,
size of image = 1/3 × size of object.
so, magnification , m = -1/3
we know, magnification of lens , m = v/u
so, v/u = -1/3
so, v = -u/3 ........(1)
now applying lens maker formula,
1/v - 1/u = 1/f
or, 1/(-u/3) - 1/u = 1/20
or, -3/u - 1/u = 1/20
or, u = -80 cm
hence, object is placed 80cm from the pole of convex lens.
i hope it helps you.