A litre of pure alcohol is added to 60 days of 30% of all solution the percentage of water in the solution is
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Answered by
0
To solve, use formula, concentration of alcohol in volume percentage = Volume of alcoholVolume of solution×100
Total volume of alcohol solution = 70ml
Concentration of alcohol solution in volume percentage = 60%
Substituting in the equation, 60 = volume of alcohol70× 100
Volume of pure alcohol = 60 × 70100 = 42m
Hope this will help you.... ✌
Total volume of alcohol solution = 70ml
Concentration of alcohol solution in volume percentage = 60%
Substituting in the equation, 60 = volume of alcohol70× 100
Volume of pure alcohol = 60 × 70100 = 42m
Hope this will help you.... ✌
Answered by
1
Explanation:
Answer:
Alcohol =
30
× 6 = 1.8 litres
100
Water = 4.2 litres
On mixing 1 litre of pure alcohol,
Percentage of water =
4.2
× 100 = 60%
7
Explanation:
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