Question

a little bit challenging solve this

Find four consecutive term in A.P. whose sum is 20 and sum of 3rd and 4th term is 1.
fast I need answer​

Answer 1

Let the four numbers in A.P be a-3d, a-d,a+d,a+3d.    ---- (1)

Given that Sum of the terms = 20.

= (a-3d) + (a-d) + (a+d) + (a+3d) = 20

4a = 20

  a = 5.    ---- (2)

a+d+a+3d=1
2a+4d=1

putting value of a
10+4d=1
4d=-9
d=-9/4


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