A load of mass 20 kg is lifted with the help of a rope at aconstant acceleration . The load covers a height of 5m in 2sec .Calculate the tension in the rope
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100N is the right answer
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Answer:
250N
Explanation:
m= 20 kg s=5m t=2s
T-mg = ma ( by free body diagram)
T =ma + mg
=m(a+g)
s= ut + 1/2 at^2
5= (0*2) + 1/2 * a* 4
a= 5/2 = 2.5
T = 20 ( 2.5 + 10) taking g= 10
T = 20 * 12.5 = 250 N
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