A loaded truck of mass 10 ton is going at a speed of 20kmph. A box of mass 2 tons slips from it and falls down on the road, then the velocity of truck
Answers
The velocity of truck when a mass of 2 tonnes fall down becomes 25kmph.
According to the law of conservation of momentum, we know that the total momentum of a body is always conserved.
According to it,
m₁v₁ = m₂v₂ [As momentum = mass × velocity]
where m₁ and v₁ are the masses and velocities of the bodies at the initial conditions respectively, and, m₂ and v₂ are the masses and velocities of the bodies at the final conditions.
From the question, m₁ = 10 tonnes and v₁ = 20kmph and,
m₂ = (10-2)tonnes = 8 tonnes. [As 2 tonne falls down from the initial 10 tonnes.]
And we have to find v₂.
So, v₂ = (m₁v₁) / m₂
= [(10 × 20) / 8] kmph
= (200/8) kmph
= 25kmph
So, final velocity = 25kmph.
Answer:
Explanation:The velocity of truck when a mass of 2 tonnes fall down becomes 25kmph.
The velocity of truck when a mass of 2 tonnes fall down becomes 25kmph.
According to the law of conservation of momentum, we know that the total momentum of a body is always conserved.
According to it,
m₁v₁ = m₂v₂ [As momentum = mass × velocity]
where m₁ and v₁ are the masses and velocities of the bodies at the initial conditions respectively, and, m₂ and v₂ are the masses and velocities of the bodies at the final conditions.
From the question, m₁ = 10 tonnes and v₁ = 20kmph and,
m₂ = (10-2)tonnes = 8 tonnes. [As 2 tonne falls down from the initial 10 tonnes.]
And we have to find v₂.
So, v₂ = (m₁v₁) / m₂
= [(10 × 20) / 8] kmph
= (200/8) kmph
= 25kmph
So, final velocity = 25kmph.