Question

a local bus carrying 40 passengers some with rs 5 tickets and the remaining with rs 7.50 tickets if the total recipts from these passengers is rs 230 find the number of passenger with rs 5 tickets

Answer 1

Let the number of people with 5rs ticket be x
Then people with 7.50rs tickets are 40-x
Value of x=5x
Value of 40-x=7.5*(40-x)
5x+300-7.5x=230
=>-2.5x=-70
X=28
People with rs 5 ticket =28
People with rs 7.50 ticket =12

Answer 2

Answer:

Number of passenger with Rs 5 tickets are 28 .

Step-by-step explanation:

Let us assume that the number of passengers with 5 rupee tickets be x .

Let us assume that the number of passengers with 7.50 rupee tickets be y .

As given

A local bus carrying 40 passengers some with Rs 5 tickets and the remaining with Rs 7.50 tickets .

if the total recipts from these passengers is Rs 230 .

Equation becomes

x + y = 40

5x + 7.5y = 230

Multiply x + y = 40 by 7.5 and subtrcted from 5x + 7.5y = 230 .

5x - 7.5x + 7.5y - 7.5y = 230 - 300

-2.5x = -70

2.5x = 70

$x = \frac{70}{2.5}$

x = 28

Therefore the number of passenger with Rs 5 tickets are 28 .