What is total and displacement in these figure
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distance covered=8+6=14m
displacement is the minimum distance between two points
of we join point A and B we get right angled triangle
length of AC is the displacement
AC^2=AB^2+BC^2
AC^2=64+36
AC^2=100
AC=10m
displacement is 10m
displacement is the minimum distance between two points
of we join point A and B we get right angled triangle
length of AC is the displacement
AC^2=AB^2+BC^2
AC^2=64+36
AC^2=100
AC=10m
displacement is 10m
Answered by
1
Displacement is the shortest straight line distance from initial position to final position.
We shall find displacement by using Pythagoras theorem as she takes a turn at 90°.
h²=a²+b²
Here a and b are given as 8 and 6 respectively.
h²=8²+6²
h²=64+36
h²=100
h=√100
h=10m
therefore, displacement is 100 m.
Distance is the total path length covered.
Distance travelled =a+b
=8+6
=14 m.
Therefore, distance travelled by seema is 14 m.
We shall find displacement by using Pythagoras theorem as she takes a turn at 90°.
h²=a²+b²
Here a and b are given as 8 and 6 respectively.
h²=8²+6²
h²=64+36
h²=100
h=√100
h=10m
therefore, displacement is 100 m.
Distance is the total path length covered.
Distance travelled =a+b
=8+6
=14 m.
Therefore, distance travelled by seema is 14 m.
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