Question

A local bus is carrying 40 passengers, some with ₹5 tickets and the remaining with ₹7.50 tickets. If the total receipts from these passengers is ₹230, find the number of passengers with ₹5 tickets.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

28 passengers

Step-by-step explanation:

let no. of passengers with ₹5ticket be x

with ₹7.50 be y

we know total no. of passengers is 40

I.e. x+y=40

y=40-x eq1

total fare =₹230

5x+7.5y=230

from eq1

5x+7.5(40-x)=230

5x-7.5x+300 =230

-2.5x=230-300

x=-70/-2.5

x=700/25

x=28

therefore no. of passengers with ₹5 ticket is 28

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