A locomotive of mass m starts moving so that its velocity varies according to the law v = a√s, where a is
constant, and s is the distance covered. Find the total work performed by all the forces which are acting on
the locomotive during the first t seconds
Answers
Answered by
0
Answer:
The acceleration w is obtained by differentiating v with respect to time.
w=
dt
dv
=
2
s
a
dt
ds
=
2
s
a
a
s
=
2
a
2
(As locomotive is in unidirectional motion)
Hence force acting on the locomotive F=mw=
2
ma
2
Let, v=0 at t=0 then the distance covered during the first t seconds
s=
2
1
wt
2
=
2
1
2
a
2
t
2
=
4
a
2
t
2
Hence the work, W=Fs=
2
ma
2
4
(a
2
t
2
)
=
8
ma
4
t
2
So, x=8
Answered by
1
x=8 BY CALCULATING ALL THE METHODS
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