A log boat travels6 km in 1hour
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Let the velocity of the boat be v km/hr and velocity of the current be u km/hr
When the boat goes in still water =v=6 km/hr
When the boat goes against the current, its velocity is =v−u=(6−u) km/hr
For distance S, time taken in still water to cover the distance =
6
S
hours
For same distance S, time taken while going against the current =
6−u
S
hours
According to given condition,
6−u
S
=3×(
6
S
)
⇒
6−u
1
=
2
1
⇒6−u=2
⇒u=4 km/hr
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