A log of wood of dimensions 2m×20cm×10cm is cut into small blocks of 10cm×5cm×4cm.How many blocks will be there in all?what will be the total surface area of all these small blocks?
Answers
Answer:
The total surface area of the cuboids is 880m².
Step-by-step explanation:
Given,
The dimensions of a log of wood = 200cm×20cm×10cm
The dimensions of a small block = 10cm×5cm×4cm
The number of small blocks that will be cut from the log of wood is
N = size of log/size of small block
N = 200×20×20/10×5×4
N = 200×2
N = 400
The surface area of the cuboid, SA = 2(lb + bh + hl)
The total surface area of cuboids, TSA = N×SA
TSA = 400×2×(10×5 + 5×4 + 4×10)
TSA = 400×2×(50 + 20 + 40)
TSA = 400×2×110
TSA = 800×110
TSA = 88000 cm²
TSA = 880 m²
Hence, the total surface area of the cuboids is 880m².
To know more about total surface area, click on the link below:
https://brainly.in/question/261282
To know more about cuboid, click on the link below:
https://brainly.in/question/835104
#SPJ2
Answer: The no of blocks will be 200cm³ and total surface area of these small blocks will be 220cm³.
Step-by-step explanation:
Given dimension of the log is 2m×20cm×10cm
as all measure is in cm, we have to change length of wood into cm that is 2m= 2×100=200cm
Volume of wood log= Length× breadth× height
⇒ 200cm ×20cm× 10cm = 40000cm³
Now, volume of the cylinder (as log of wood is in cylindrical shape) cut into small blocks are like
Volume of small blocks = Length ×breadth ×height
⇒ 10 cm×5cm ×4cm= 200cm³
No of small blocks= volume of log of wood÷ volume of small blocks
⇒ 40000cm³÷200cm³ = 200cm³
Now the total surface area of all these small blocks
Surface area of cylinder= 2 (lb×bh×hl)
total surface area of small wooden blocks are
⇒ 2(10×5+5×4+4×10) = 2×110cm³=220cm³
To know more about wood log dimensions equations click the link
https://brainly.in/question/30455174
#SPJ2