Question

A logic circuit has three inputs, A, B and C. It generates an output 1 only under following conditions: A = 0, B = 0, C = 0
A = 0, B = 1, C = 1
A = 1, B = 0, C = 1
A = 1, B = 1, C = 1
Design a combinational circuit for this system.

Answer 1

1. Use or gate for A,B and initiate the result of A+B . C =1

2. Same as 1 one
3. Use and gate A.B.C

I hope you got your answer

Answer 2

Answer:

Consider the attachment.

Explanation:

• Make a K-map with the help of Truth table as per your data (Truth table in the attachment).
• Use that K-map to get the Boolean Expression and simplify it down.

The expression I got was:

A'B'C' + A'BC + AB'C + ABC

Simplifying it

= A'B'C + A'BC + AC(B'+B)

=  A'B'C' + A'BC + AC

= A'B'C' + C(A'B + A )         [ (X'Y+X) = (X+Y) ]

= A'B'C' + C(A+B)

= A'B'C' + AC+ CB

Now draw the logic circuit using this data,