A long block A is at rest on a smooth horizontal surface. A small block B whose mass is half of A, isplaced on A at one end projected along A with some velocity v. The coefficient of friction betweenthe block is u
Answers
Answered by
0
Answer:
ANSWER
As there are no external forces acting on the 'A + B' system, its total momentum is conserved. If the masses of A and B are 2m and 2 respectively, and v is the final common velocity, mu=(m+2m)v or v=u/3
Work done against friction = loss in KE =
2
1
mu
2
−
2
1
(3m)v
2
=
2
1
mu
2
−
2
1
(3m)
9
u
2
=
2
1
mu
2
[1−
3
1
]=
3
2
×
2
1
mu
2
The force of friction between the blocks is μmg.
Acceleration of A (to the right) =a
1
=
2m
μmg
=
2
μg
Acceleration of B (to the left) =a
2
=
m
μmg
=μg
Acceleration of A relative to B =a
1
−(−a
2
)=
2
3
μg.
Similar questions