A long capillary tube of mass  gram, radius 2 mm and negligible thickness, is partially immersed in a liquid of surface tension 0.1N/m. Take angle of contact zero and neglect buoyant force of liquid. The force required to hold the tube vertically will be (g = 10 m/s2 )
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Consider the formula
F = mg + 2 S(2π r )
Assumed,
m = π gm, r = 2 mm = 2 × 10-3 m, S = 0. 1N/m , g = 10 m/ s 2
F = 10π + 2 × 0. 1(2 × π × 2 × 10 ) −3
F = 10. 8π mN
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