Math, asked by kayt699, 1 year ago

Joseph scored 8 Makes fewer than Amit in an examination . Kumar scored 12 marks more than amit . In total they scored 205 marks . What was the score of joseph ?

Answers

Answered by hussain036
1
A - J =8
A =8 +J
ALSO K - A = 12
K = 12 + A
K = 12 + (8 + J). (since A = 8 + J)
and A+K+J = 205
so 8+J + 12 + 8+J + J = 205
3J + 28 = 205
3J = 177
J = 177/3
J = 59
Answered by Anonymous
2

\textbf{\underline{\underline{According\:to\:the\:Question}}}

\textbf{\underline{Assumption}}

{\boxed{\sf\:{Marks\;scored\;by\;Amit}}}

= p

Hence,

{\boxed{\sf\:{Marks\;scored\;by\;Joseph}}}

= p - 8

Also,

{\boxed{\sf\:{Marks\;scored\;by\;Kumar}}}

= p + 12

Total marks scored by Amit + Joseph + kumar

= 205

\textbf{\underline{Situation}}

p + p - 8 + p + 12 = 205

3p + 4 = 205

3p = 205 - 4

3p = 201

\tt{\rightarrow p=\dfrac{201}{3}}

⇒ p = 67

Hence we get,

\textbf{\underline{Amit=67\;Marks}}

\textbf{\underline{Joseph\;Marks}}

= 67 - 8

= 59 marks

Therefore,

\textbf{\underline{Joseph=59\;Marks}}

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