Question

A long pole is made to stand against a wall in such a way that its foot is 16 m from the wall and its top reaches a window 12m above the ground. Find the length of the pole.

Answer 1

Answer:

${16}^{2} + {12}^{2} = {x}^{2} \\ 256 + 144 = {x}^{2} \\ 400 = {x}^{2} \\ x = \sqrt{400} \\ x = 20$

Answer 2

The length of the pole is 20 m .

Explanation:

Given : A long pole is made to stand against a wall in such a way that its foot is 16 m from the wall and its top reaches a window 12m above the ground.

Since the wall stands vertical to the ground makes a right angle.

Therefore the triangle formed by pole and wall with ground is right angle , where hypotenuse = pole.

Let 'H' be the length of the pole.

According to the Pythagoras theorem , we have

$H^2=16^2+12^2\\\\ H^2=256+144\\\\ H^2=400\\\\ H=\sqrt{400}=20$

Hence, the length of the pole is 20 m .

# Learn more :

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