Question

A long straight current carrying wire passes normally through the centre of circular loop. If the current through the wire increases, will there be an induced emf in the loop? Justify.
[Delhi 2017]

Answer 1

Explanation:

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Answer 2

Answer:

The induced emf in the loop $=\frac{40}{4 \pi} 4 \pi i$.

Explanation:

Step 1: Increase has a number of popular synonyms, including augment, enlarge, and magnify. While all of these verbs mean "to make or become larger," "increase" implies progressive growth in size, amount, or intensity when used in the passive. When used in the active, however, it could also suggest simple addition rather than progressive growth. With age, his girth grew larger.

Step 2: Something's number, level, or amount grows if you increase it or if you do it yourself. Something becomes greater if the quantity, level, or amount of it increases.Consider a cable carrying current for a moment.Let's take a wire carrying electricity as an example.

The magnitude of the magnetic field at point p can be given as,$B=\frac{l_0}{4 \pi} \frac{2 \pi i}{\pi}$

We must calculate the tine integral along the circular path to determine the overall magnetic field.

$\begin{aligned}& \oint B \cdot d l \\= & \oint \frac{20}{4 \pi} \frac{2 \pi i}{\pi} d t \\= & \frac{l 0}{4 \pi} \frac{2 \pi i}{r} \oint d l \\= & \frac{40}{4 \pi} 4 \pi i\end{aligned}$

$=\frac{l i 0}{4 \pi} \frac{2 \pi i}{x} \cdot 2 \pi x$

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