Question

. A long straight solid conductor of
radius 5 cm carries a current of 2 A, which is uniformly
distributed over its circular cross-section. Find the
magnetic field induction at a distance of 3 cm from the
axis of the conductor.
with explanation​

Answer 1

Answer:

The magnetic field is 0.48×10⁻⁵ T

Explanation:

Radius r = 5cm

Current I = 2A

Distance d = 3cm

Now, the magnetic field at a point inside the conductor

B = μ₀Id / 2πr²

B = 4π×10⁻⁷×2×3×10⁻² /   2π×25×10⁻⁴

B = 0.48×10⁻⁵

B = 0.48×10⁻⁵ T

Hence, the magnetic field is 0.48×10⁻⁵ T